# Bit Counting in Golang

## The challenge

Write a function that takes an integer as input, and returns the number of bits that are equal to one in the binary representation of that number. You can guarantee that input is non-negative.

*Example*: The binary representation of `1234`

is `10011010010`

, so the function should return `5`

in this case

## The solution in Golang

Option 1:

```
package solution
import "math/bits"
func CountBits(n uint) int {
return bits.OnesCount(n)
}
```

Option 2:

```
package solution
import "math/bits"
var CountBits = bits.OnesCount
```

Option 3:

```
package solution
func CountBits(n uint) int {
var res int = 0
for (n>0) {
if (n & 1 == 1) {
res = res + 1
}
n = n >> 1
}
return res
}
```

## Test cases to validate our solution

```
package solution_test
import (
. "github.com/onsi/ginkgo"
. "github.com/onsi/gomega"
)
var _ = Describe("CountBits()", func() {
It("basic tests", func() {
Expect(CountBits(0)).To(Equal(0))
Expect(CountBits(4)).To(Equal(1))
Expect(CountBits(7)).To(Equal(3))
Expect(CountBits(9)).To(Equal(2))
Expect(CountBits(10)).To(Equal(2))
})
})
```