# Most Digits from List in Python

## The challenge

Find the number with the most digits.

If two numbers in the argument array have the same number of digits, return the first one in the array.

## The solution in Python code

Option 1:

```
def find_longest(xs):
return max(xs, key=lambda x: len(str(x)))
```

Option 2:

```
def find_longest(arr):
arr.sort(reverse=True)
return arr[0]
```

Option 3:

```
def find_longest(arr):
max_lenght = 0
max_index = 0
for cur_num in arr:
lenght = len(str(cur_num))
if lenght > max_lenght:
max_lenght = lenght
max_index = arr.index(cur_num)
return arr[max_index]
```

## Test cases to validate our solution

```
import test
from solution import find_longest
@test.describe("Fixed Tests")
def fixed_tests():
@test.it('Basic Test Cases')
def basic_test_cases():
test.assert_equals(find_longest([1, 10, 100]), 100)
test.assert_equals(find_longest([9000, 8, 800]), 9000)
test.assert_equals(find_longest([8, 900, 500]), 900)
test.assert_equals(find_longest([3, 40000, 100]), 40000)
test.assert_equals(find_longest([1, 200, 100000]), 100000)
@test.describe("Random tests")
def random_tests():
from random import randint
from functools import reduce
sol=lambda arr: reduce(lambda a,b: b if len(str(a))<len(str(b)) else a,arr)
for _ in range(40):
arr=[randint(1,10**randint(1,20)) for q in range(randint(1,50))]
expected = sol(arr)
@test.it(f"Testing for find_longest({arr})")
def _():
test.assert_equals(find_longest(arr[:]),expected)
```